25 June 2022

C++ 核心指南目录

理由

编程语言确保 T& 指向一个对象。所以不需要测试是否为 nullptr

返回引用不转移所有权。

例子

// -*- compile-command: "g++ -std=c++20 code.cpp && ./a"; -*-
#include <iostream>
#include <array>
#include <gsl/gsl>
using namespace std;
using namespace gsl;

class wheel {
    float pressure;
public:
    wheel(float p = 100): pressure(p){}
    friend ostream& operator<<(ostream& o, wheel& w);
};

ostream& operator<<(ostream& o, wheel& w) {
    o << "wheel's pressure is " << w.pressure << endl;
}

class Car
{
    array<wheel, 4> w;
    // ...
public:
    Car(){}
    wheel& get_wheel(int i) { Expects(i < w.size()); return w[i]; }
    // ...
};

void use()
{
    Car c;
    wheel& w0 = c.get_wheel(0); // w0 has the same lifetime as c
    cout << w0;
}

int main()
{
    use();
    return 0;
}
wheel's pressure is 100

强化

  • 注意函数返回值是引用的话,函数是不可能返回 nullptr